A bag contains 3 red and 2 blue balls. If one ball is drawn at random, what is the probability the ball is red?

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Multiple Choice

A bag contains 3 red and 2 blue balls. If one ball is drawn at random, what is the probability the ball is red?

Explanation:
When you draw one ball at random from a bag, each ball is equally likely to be chosen. The probability of getting red is the number of red balls divided by the total number of balls. There are 3 red balls and 5 balls total, so the probability is 3/5, which equals 0.6. The other numbers don’t fit because they’d require a different count of red balls among the five total (0.4 would be 2 red out of 5, 0.5 would imply a 2.5 red out of 5 which isn’t possible, and 0.7 would imply 3.5 red out of 5, which also isn’t possible). Therefore, the probability of drawing a red ball is 0.6.

When you draw one ball at random from a bag, each ball is equally likely to be chosen. The probability of getting red is the number of red balls divided by the total number of balls. There are 3 red balls and 5 balls total, so the probability is 3/5, which equals 0.6.

The other numbers don’t fit because they’d require a different count of red balls among the five total (0.4 would be 2 red out of 5, 0.5 would imply a 2.5 red out of 5 which isn’t possible, and 0.7 would imply 3.5 red out of 5, which also isn’t possible). Therefore, the probability of drawing a red ball is 0.6.

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